3 Pulwars

mariusgmioc · 9th October 2019, 11:53 PM

It is as I said, bent laterally (say "z" axis, where longitudinal ,direction is "x" axis, and the direction of the curvature of the blade is the "y" axis) then straightened up!

The blade has a triangular cross-section, with more material at the spine and when the blade is bent laterally (along z axis) there is more material that extends near the spine than near the edge. Then, when the blade is straightened up, the extended material near the spine compresses less than the material near the edge, thus resulting the "counter-curvature" along the y axis that is in the opposite direction of the curvature of the blade.

9th October 2019, 11:53 PM	#24
mariusgmioc Member Join Date: Sep 2014 Location: Austria Posts: 1,911	It is as I said, bent laterally (say "z" axis, where longitudinal ,direction is "x" axis, and the direction of the curvature of the blade is the "y" axis) then straightened up! The blade has a triangular cross-section, with more material at the spine and when the blade is bent laterally (along z axis) there is more material that extends near the spine than near the edge. Then, when the blade is straightened up, the extended material near the spine compresses less than the material near the edge, thus resulting the "counter-curvature" along the y axis that is in the opposite direction of the curvature of the blade. Last edited by mariusgmioc; 10th October 2019 at 10:05 AM.